Consider an array of numeric strings where each string is a positive number with anywhere from to digits. Sort the array's elements in non-decreasing, or ascending order of their integer values and return the sorted array.
Example
Return the array ['1', '3', '150', '200'].
Function Description
Complete the bigSorting function in the editor below.
bigSorting has the following parameter(s):
- string unsorted[n]: an unsorted array of integers as strings
Returns
- string[n]: the array sorted in numerical order
Input Format
The first line contains an integer, , the number of strings in .
Each of the subsequent lines contains an integer string, .
Constraints
- Each string is guaranteed to represent a positive integer.
- There will be no leading zeros.
- The total number of digits across all strings in is between and (inclusive).
Sample Input 0
6
31415926535897932384626433832795
1
3
10
3
5
Sample Output 0
1
3
3
5
10
31415926535897932384626433832795
Explanation 0
The initial array of strings is . When we order each string by the real-world integer value it represents, we get:
We then print each value on a new line, from smallest to largest.
Sample Input 1
8
1
2
100
12303479849857341718340192371
3084193741082937
3084193741082938
111
200
Sample Output 1
1
2
100
111
200
3084193741082937
3084193741082938
12303479849857341718340192371
문제 풀이
기존 생각방식대로 문자열을 숫자로 바꾸고 하면 시간 초과가 난다.
그래서 sorted 와 람다를 이용해서 타임아웃에서 빠져나오기!
#!/bin/python3
import math
import os
import random
import re
import sys
#
# Complete the 'bigSorting' function below.
#
# The function is expected to return a STRING_ARRAY.
# The function accepts STRING_ARRAY unsorted as parameter.
#
def bigSorting(unsorted):
return sorted(unsorted,key = lambda x : (len(x),x))
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
n = int(input().strip())
unsorted = []
for _ in range(n):
unsorted_item = input()
unsorted.append(unsorted_item)
result = bigSorting(unsorted)
fptr.write('\n'.join(result))
fptr.write('\n')
fptr.close()
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